3x^2-30x-1056=0

Solution for 3x^2-30x-1056=0 equation:

3x^2-30x-1056=0

a = 3; b = -30; c = -1056;
Δ = b2-4ac
Δ = -302-4·3·(-1056)
Δ = 13572
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{13572}=\sqrt{36*377}=\sqrt{36}*\sqrt{377}=6\sqrt{377}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-6\sqrt{377}}{2*3}=\frac{30-6\sqrt{377}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+6\sqrt{377}}{2*3}=\frac{30+6\sqrt{377}}{6}
$